Base | Representation |
---|---|
bin | 11111111010011001000110… |
… | …011101011100001011111001 |
3 | 200101221112100210120201120102 |
4 | 133322121012131130023321 |
5 | 121344012122043441213 |
6 | 1214300513030005145 |
7 | 41364051313010300 |
oct | 3772310635341371 |
9 | 611845323521512 |
10 | 140352123421433 |
11 | 407a2001776540 |
12 | 138a92221a67b5 |
13 | 60411c11aa6c1 |
14 | 2693116b85437 |
15 | 1135d32b82158 |
hex | 7fa64675c2f9 |
140352123421433 has 24 divisors (see below), whose sum is σ = 178186729652064. Its totient is φ = 109317677784000.
The previous prime is 140352123421417. The next prime is 140352123421463. The reversal of 140352123421433 is 334124321253041.
It is not a de Polignac number, because 140352123421433 - 24 = 140352123421417 is a prime.
It is not an unprimeable number, because it can be changed into a prime (140352123421463) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 55443143 + ... + 57919308.
It is an arithmetic number, because the mean of its divisors is an integer number (7424447068836).
Almost surely, 2140352123421433 is an apocalyptic number.
It is an amenable number.
140352123421433 is a deficient number, since it is larger than the sum of its proper divisors (37834606230631).
140352123421433 is a wasteful number, since it uses less digits than its factorization.
140352123421433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113364773 (or 113364766 counting only the distinct ones).
The product of its (nonzero) digits is 207360, while the sum is 38.
Adding to 140352123421433 its reverse (334124321253041), we get a palindrome (474476444674474).
The spelling of 140352123421433 in words is "one hundred forty trillion, three hundred fifty-two billion, one hundred twenty-three million, four hundred twenty-one thousand, four hundred thirty-three".
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