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140352576333113 is a prime number
BaseRepresentation
bin11111111010011001100001…
…011101001010010100111001
3200101221120112100211000121002
4133322121201131022110321
5121344014034020124423
61214301030005254345
741364065452464434
oct3772314135122471
9611846470730532
10140352576333113
11407a22143a0811
12138a9329a043b5
136041263c86791
14269315ada081b
151135d5c7e8228
hex7fa66174a539

140352576333113 has 2 divisors, whose sum is σ = 140352576333114. Its totient is φ = 140352576333112.

The previous prime is 140352576333103. The next prime is 140352576333119. The reversal of 140352576333113 is 311333675253041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96475769995264 + 43876806337849 = 9822208^2 + 6623957^2 .

It is a cyclic number.

It is not a de Polignac number, because 140352576333113 - 246 = 69983832155449 is a prime.

It is a super-2 number, since 2×1403525763331132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140352576333119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70176288166556 + 70176288166557.

It is an arithmetic number, because the mean of its divisors is an integer number (70176288166557).

Almost surely, 2140352576333113 is an apocalyptic number.

It is an amenable number.

140352576333113 is a deficient number, since it is larger than the sum of its proper divisors (1).

140352576333113 is an equidigital number, since it uses as much as digits as its factorization.

140352576333113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2041200, while the sum is 47.

The spelling of 140352576333113 in words is "one hundred forty trillion, three hundred fifty-two billion, five hundred seventy-six million, three hundred thirty-three thousand, one hundred thirteen".