Search a number
-
+
14035304353 = 77128240049
BaseRepresentation
bin11010001001001000…
…11011111110100001
31100020010220100001011
431010210123332201
5212221014214403
610240413140521
71004544055450
oct150444337641
940203810034
1014035304353
115a52621994
12287848a741
131428a20325
14972066b97
155722a8a6d
hex34491bfa1

14035304353 has 8 divisors (see below), whose sum is σ = 16266268800. Its totient is φ = 11860820160.

The previous prime is 14035304341. The next prime is 14035304401. The reversal of 14035304353 is 35340353041.

14035304353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14035304353 - 25 = 14035304321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14035304333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14119528 + ... + 14120521.

It is an arithmetic number, because the mean of its divisors is an integer number (2033283600).

Almost surely, 214035304353 is an apocalyptic number.

It is an amenable number.

14035304353 is a deficient number, since it is larger than the sum of its proper divisors (2230964447).

14035304353 is an equidigital number, since it uses as much as digits as its factorization.

14035304353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28240127.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 14035304353 its reverse (35340353041), we get a palindrome (49375657394).

The spelling of 14035304353 in words is "fourteen billion, thirty-five million, three hundred four thousand, three hundred fifty-three".

Divisors: 1 7 71 497 28240049 197680343 2005043479 14035304353