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140354304520135 = 561473879711061
BaseRepresentation
bin11111111010011011001000…
…011101101010111111000111
3200101221201222210201000111211
4133322123020131222333013
5121344031103424121020
61214301513302312251
741364156336024526
oct3772331035527707
9611851883630454
10140354304520135
11407a2a20966252
12138a9730728687
13604147b021a54
1426932827024bd
151135e0e3b885a
hex7fa6c876afc7

140354304520135 has 16 divisors (see below), whose sum is σ = 171189863852832. Its totient is φ = 110440389398400.

The previous prime is 140354304520121. The next prime is 140354304520141. The reversal of 140354304520135 is 531025403453041.

It is not a de Polignac number, because 140354304520135 - 25 = 140354304520103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9597505 + ... + 19308565.

It is an arithmetic number, because the mean of its divisors is an integer number (10699366490802).

Almost surely, 2140354304520135 is an apocalyptic number.

140354304520135 is a deficient number, since it is larger than the sum of its proper divisors (30835559332697).

140354304520135 is an equidigital number, since it uses as much as digits as its factorization.

140354304520135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9758514.

The product of its (nonzero) digits is 432000, while the sum is 40.

Adding to 140354304520135 its reverse (531025403453041), we get a palindrome (671379707973176).

The spelling of 140354304520135 in words is "one hundred forty trillion, three hundred fifty-four billion, three hundred four million, five hundred twenty thousand, one hundred thirty-five".

Divisors: 1 5 61 305 47387 236935 2890607 9711061 14453035 48555305 592374721 2961873605 460178047607 2300890238035 28070860904027 140354304520135