Base | Representation |
---|---|
bin | 11010001001010010… |
… | …00000100000011001 |
3 | 1100020020011012122221 |
4 | 31010221000200121 |
5 | 212221321040203 |
6 | 10240454544041 |
7 | 1004560205653 |
oct | 150451004031 |
9 | 40206135587 |
10 | 14036502553 |
11 | 5a53270137 |
12 | 2878968021 |
13 | 142904c818 |
14 | 9722996d3 |
15 | 572443abd |
hex | 344a40819 |
14036502553 has 2 divisors, whose sum is σ = 14036502554. Its totient is φ = 14036502552.
The previous prime is 14036502517. The next prime is 14036502749. The reversal of 14036502553 is 35520563041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11361854464 + 2674648089 = 106592^2 + 51717^2 .
It is a cyclic number.
It is not a de Polignac number, because 14036502553 - 221 = 14034405401 is a prime.
It is a super-3 number, since 3×140365025533 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (14036503553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7018251276 + 7018251277.
It is an arithmetic number, because the mean of its divisors is an integer number (7018251277).
Almost surely, 214036502553 is an apocalyptic number.
It is an amenable number.
14036502553 is a deficient number, since it is larger than the sum of its proper divisors (1).
14036502553 is an equidigital number, since it uses as much as digits as its factorization.
14036502553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 34.
The spelling of 14036502553 in words is "fourteen billion, thirty-six million, five hundred two thousand, five hundred fifty-three".
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