Base | Representation |
---|---|
bin | 11111111010110000011111… |
… | …000100110011111110001011 |
3 | 200102000221011200122220220022 |
4 | 133322300133010303332023 |
5 | 121344420033002120421 |
6 | 1214320224343451055 |
7 | 41365630453210352 |
oct | 3772603704637613 |
9 | 612027150586808 |
10 | 140377232457611 |
11 | 40801717106006 |
12 | 138b206b156a8b |
13 | 604369319c666 |
14 | 26944197d2999 |
15 | 11368021e17ab |
hex | 7fac1f133f8b |
140377232457611 has 2 divisors, whose sum is σ = 140377232457612. Its totient is φ = 140377232457610.
The previous prime is 140377232457599. The next prime is 140377232457613. The reversal of 140377232457611 is 116754232773041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140377232457611 - 242 = 135979185946507 is a prime.
Together with 140377232457613, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (140377232457613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70188616228805 + 70188616228806.
It is an arithmetic number, because the mean of its divisors is an integer number (70188616228806).
Almost surely, 2140377232457611 is an apocalyptic number.
140377232457611 is a deficient number, since it is larger than the sum of its proper divisors (1).
140377232457611 is an equidigital number, since it uses as much as digits as its factorization.
140377232457611 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5927040, while the sum is 53.
The spelling of 140377232457611 in words is "one hundred forty trillion, three hundred seventy-seven billion, two hundred thirty-two million, four hundred fifty-seven thousand, six hundred eleven".
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