Base | Representation |
---|---|
bin | 1100110001001111000111… |
… | …1011111000101101000111 |
3 | 1211201012201120210211001121 |
4 | 3030103301323320231013 |
5 | 3320012421101144033 |
6 | 45505520441534411 |
7 | 2646233406015115 |
oct | 314236173705507 |
9 | 54635646724047 |
10 | 14040012131143 |
11 | 4523376909a69 |
12 | 16a906b7a4407 |
13 | 7aac766930ab |
14 | 36777c4b6ab5 |
15 | 19532d9ce62d |
hex | cc4f1ef8b47 |
14040012131143 has 4 divisors (see below), whose sum is σ = 14124084060240. Its totient is φ = 13955940202048.
The previous prime is 14040012131137. The next prime is 14040012131279. The reversal of 14040012131143 is 34113121004041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14040012131143 - 29 = 14040012130631 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14040012111143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42035964298 + ... + 42035964631.
It is an arithmetic number, because the mean of its divisors is an integer number (3531021015060).
Almost surely, 214040012131143 is an apocalyptic number.
14040012131143 is a deficient number, since it is larger than the sum of its proper divisors (84071929097).
14040012131143 is an equidigital number, since it uses as much as digits as its factorization.
14040012131143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84071929096.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14040012131143 its reverse (34113121004041), we get a palindrome (48153133135184).
The spelling of 14040012131143 in words is "fourteen trillion, forty billion, twelve million, one hundred thirty-one thousand, one hundred forty-three".
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