140401140113 has 6 divisors (see below), whose sum is σ = 152032003974. Its totient is φ = 129601052256.

The previous prime is 140401140109. The next prime is 140401140161. The reversal of 140401140113 is 311041104041.

It can be written as a sum of positive squares in 3 ways, for example, as 1404150784 + 138996989329 = 37472^2 + 372823^2 .

It is not a de Polignac number, because 140401140113 - 2² = 140401140109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140401140163) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 415387820 + ... + 415388157.

It is an arithmetic number, because the mean of its divisors is an integer number (25338667329).

Almost surely, 2^140401140113 is an apocalyptic number.

140401140113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

140401140113 is a deficient number, since it is larger than the sum of its proper divisors (11630863861).

140401140113 is an equidigital number, since it uses as much as digits as its factorization.

140401140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 830776003 (or 830775990 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 140401140113 its reverse (311041104041), we get a palindrome (451442244154).

The spelling of 140401140113 in words is "one hundred forty billion, four hundred one million, one hundred forty thousand, one hundred thirteen".