1404031312483 has 2 divisors, whose sum is σ = 1404031312484. Its totient is φ = 1404031312482.

The previous prime is 1404031312351. The next prime is 1404031312501. The reversal of 1404031312483 is 3842131304041.

It is a strong prime.

It is an emirp because it is prime and its reverse (3842131304041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1404031312483 is a prime.

It is not a weakly prime, because it can be changed into another prime (1404031315483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702015656241 + 702015656242.

It is an arithmetic number, because the mean of its divisors is an integer number (702015656242).

Almost surely, 2^{1404031312483} is an apocalyptic number.

1404031312483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1404031312483 is an equidigital number, since it uses as much as digits as its factorization.

1404031312483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 34.

The spelling of 1404031312483 in words is "one trillion, four hundred four billion, thirty-one million, three hundred twelve thousand, four hundred eighty-three".