Base | Representation |
---|---|
bin | 10100011011100110110… |
… | …010011010000111011111 |
3 | 11222020001100121200101201 |
4 | 110123212302122013133 |
5 | 141000424003443401 |
6 | 2553000355420331 |
7 | 203303130146203 |
oct | 24334662320737 |
9 | 4866040550351 |
10 | 1404031312351 |
11 | 4a14a0088998 |
12 | 1a813b2b46a7 |
13 | a2526b6c9b5 |
14 | 4bd53b90b03 |
15 | 267c701cb01 |
hex | 146e6c9a1df |
1404031312351 has 2 divisors, whose sum is σ = 1404031312352. Its totient is φ = 1404031312350.
The previous prime is 1404031312309. The next prime is 1404031312483. The reversal of 1404031312351 is 1532131304041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1404031312351 - 231 = 1401883828703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1404031312301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702015656175 + 702015656176.
It is an arithmetic number, because the mean of its divisors is an integer number (702015656176).
Almost surely, 21404031312351 is an apocalyptic number.
1404031312351 is a deficient number, since it is larger than the sum of its proper divisors (1).
1404031312351 is an equidigital number, since it uses as much as digits as its factorization.
1404031312351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 1404031312351 its reverse (1532131304041), we get a palindrome (2936162616392).
The spelling of 1404031312351 in words is "one trillion, four hundred four billion, thirty-one million, three hundred twelve thousand, three hundred fifty-one".
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