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140403233119 is a prime number
BaseRepresentation
bin1000001011000010101…
…1110101000101011111
3111102101221110020121011
42002300223311011133
54300021211424434
6144300024320051
713100215535032
oct2026053650537
9442357406534
10140403233119
11545a9a68156
1223264913027
1310317296086
146b1cdd5019
1539bb322e64
hex20b0af515f

140403233119 has 2 divisors, whose sum is σ = 140403233120. Its totient is φ = 140403233118.

The previous prime is 140403233111. The next prime is 140403233129. The reversal of 140403233119 is 911332304041.

140403233119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 140403233119 - 23 = 140403233111 is a prime.

It is a super-3 number, since 3×1404032331193 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140403233111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70201616559 + 70201616560.

It is an arithmetic number, because the mean of its divisors is an integer number (70201616560).

Almost surely, 2140403233119 is an apocalyptic number.

140403233119 is a deficient number, since it is larger than the sum of its proper divisors (1).

140403233119 is an equidigital number, since it uses as much as digits as its factorization.

140403233119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 31.

The spelling of 140403233119 in words is "one hundred forty billion, four hundred three million, two hundred thirty-three thousand, one hundred nineteen".