140413410443113 has 4 divisors (see below), whose sum is σ = 146518341331968. Its totient is φ = 134308479554260.

The previous prime is 140413410443099. The next prime is 140413410443149. The reversal of 140413410443113 is 311344014314041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140413410443113 - 2⁵ = 140413410443081 is a prime.

It is a super-2 number, since 2×140413410443113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140413410443183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3052465444393 + ... + 3052465444438.

It is an arithmetic number, because the mean of its divisors is an integer number (36629585332992).

Almost surely, 2^{140413410443113} is an apocalyptic number.

It is an amenable number.

140413410443113 is a deficient number, since it is larger than the sum of its proper divisors (6104930888855).

140413410443113 is an equidigital number, since it uses as much as digits as its factorization.

140413410443113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6104930888854.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 140413410443113 its reverse (311344014314041), we get a palindrome (451757424757154).

The spelling of 140413410443113 in words is "one hundred forty trillion, four hundred thirteen billion, four hundred ten million, four hundred forty-three thousand, one hundred thirteen".