140415040401533 has 4 divisors (see below), whose sum is σ = 140997675424188. Its totient is φ = 139832405378880.

The previous prime is 140415040401527. The next prime is 140415040401557. The reversal of 140415040401533 is 335104040514041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 65570429368249 + 74844611033284 = 8097557^2 + 8651278^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140415040401533 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140415040401493 and 140415040401502.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140415040401733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 291317510966 + ... + 291317511447.

It is an arithmetic number, because the mean of its divisors is an integer number (35249418856047).

Almost surely, 2^{140415040401533} is an apocalyptic number.

It is an amenable number.

140415040401533 is a deficient number, since it is larger than the sum of its proper divisors (582635022655).

140415040401533 is an equidigital number, since it uses as much as digits as its factorization.

140415040401533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 582635022654.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 140415040401533 its reverse (335104040514041), we get a palindrome (475519080915574).

The spelling of 140415040401533 in words is "one hundred forty trillion, four hundred fifteen billion, forty million, four hundred one thousand, five hundred thirty-three".