14042011412353 has 4 divisors (see below), whose sum is σ = 14050170630468. Its totient is φ = 14033852194240.

The previous prime is 14042011412327. The next prime is 14042011412459. The reversal of 14042011412353 is 35321411024041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10317759864129 + 3724251548224 = 3212127^2 + 1929832^2 .

It is a cyclic number.

It is not a de Polignac number, because 14042011412353 - 2⁴¹ = 11842988156801 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14042011412053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4079606476 + ... + 4079609917.

It is an arithmetic number, because the mean of its divisors is an integer number (3512542657617).

Almost surely, 2^{14042011412353} is an apocalyptic number.

It is an amenable number.

14042011412353 is a deficient number, since it is larger than the sum of its proper divisors (8159218115).

14042011412353 is an equidigital number, since it uses as much as digits as its factorization.

14042011412353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8159218114.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 14042011412353 its reverse (35321411024041), we get a palindrome (49363422436394).

The spelling of 14042011412353 in words is "fourteen trillion, forty-two billion, eleven million, four hundred twelve thousand, three hundred fifty-three".