14042040113 has 4 divisors (see below), whose sum is σ = 14092012068. Its totient is φ = 13992068160.

The previous prime is 14042040107. The next prime is 14042040167. The reversal of 14042040113 is 31104024041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31104024041 = 17 ⋅1829648473.

It can be written as a sum of positive squares in 2 ways, for example, as 10943670544 + 3098369569 = 104612^2 + 55663^2 .

It is a cyclic number.

It is not a de Polignac number, because 14042040113 - 2²⁰ = 14040991537 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14042045113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24985556 + ... + 24986117.

It is an arithmetic number, because the mean of its divisors is an integer number (3523003017).

Almost surely, 2^14042040113 is an apocalyptic number.

It is an amenable number.

14042040113 is a deficient number, since it is larger than the sum of its proper divisors (49971955).

14042040113 is an equidigital number, since it uses as much as digits as its factorization.

14042040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49971954.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 14042040113 its reverse (31104024041), we get a palindrome (45146064154).

The spelling of 14042040113 in words is "fourteen billion, forty-two million, forty thousand, one hundred thirteen".