14042211320131 has 4 divisors (see below), whose sum is σ = 14042845216312. Its totient is φ = 14041577423952.

The previous prime is 14042211320119. The next prime is 14042211320143. The reversal of 14042211320131 is 13102311224041.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (14042211320119) and next prime (14042211320143).

It is a cyclic number.

It is not a de Polignac number, because 14042211320131 - 2⁴¹ = 11843188064579 is a prime.

It is a super-2 number, since 2×14042211320131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14042211320096 and 14042211320105.

It is not an unprimeable number, because it can be changed into a prime (14042211320161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316914861 + ... + 316959166.

It is an arithmetic number, because the mean of its divisors is an integer number (3510711304078).

Almost surely, 2^{14042211320131} is an apocalyptic number.

14042211320131 is a deficient number, since it is larger than the sum of its proper divisors (633896181).

14042211320131 is an equidigital number, since it uses as much as digits as its factorization.

14042211320131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 633896180.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14042211320131 its reverse (13102311224041), we get a palindrome (27144522544172).

The spelling of 14042211320131 in words is "fourteen trillion, forty-two billion, two hundred eleven million, three hundred twenty thousand, one hundred thirty-one".