140423023096121 has 2 divisors, whose sum is σ = 140423023096122. Its totient is φ = 140423023096120.

The previous prime is 140423023096093. The next prime is 140423023096123. The reversal of 140423023096121 is 121690320324041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105772894314025 + 34650128782096 = 10284595^2 + 5886436^2 .

It is a cyclic number.

It is not a de Polignac number, because 140423023096121 - 2¹⁴ = 140423023079737 is a prime.

Together with 140423023096123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (140423023096123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70211511548060 + 70211511548061.

It is an arithmetic number, because the mean of its divisors is an integer number (70211511548061).

Almost surely, 2^{140423023096121} is an apocalyptic number.

It is an amenable number.

140423023096121 is a deficient number, since it is larger than the sum of its proper divisors (1).

140423023096121 is an equidigital number, since it uses as much as digits as its factorization.

140423023096121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 38.

The spelling of 140423023096121 in words is "one hundred forty trillion, four hundred twenty-three billion, twenty-three million, ninety-six thousand, one hundred twenty-one".