Base | Representation |
---|---|
bin | 11010001001111111… |
… | …00011100101111011 |
3 | 1100020122021111212111 |
4 | 31010333203211323 |
5 | 212224324212220 |
6 | 10241225353151 |
7 | 1004661354601 |
oct | 150477434573 |
9 | 40218244774 |
10 | 14042413435 |
11 | 5a56638066 |
12 | 287a9387b7 |
13 | 142a33c09b |
14 | 972d97871 |
15 | 572c1015a |
hex | 344fe397b |
14042413435 has 4 divisors (see below), whose sum is σ = 16850896128. Its totient is φ = 11233930744.
The previous prime is 14042413421. The next prime is 14042413481. The reversal of 14042413435 is 53431424041.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53431424041 = 127549 ⋅418909.
It is a cyclic number.
It is not a de Polignac number, because 14042413435 - 25 = 14042413403 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14042413397 and 14042413406.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1404241339 + ... + 1404241348.
It is an arithmetic number, because the mean of its divisors is an integer number (4212724032).
Almost surely, 214042413435 is an apocalyptic number.
14042413435 is a deficient number, since it is larger than the sum of its proper divisors (2808482693).
14042413435 is an equidigital number, since it uses as much as digits as its factorization.
14042413435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2808482692.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 14042413435 its reverse (53431424041), we get a palindrome (67473837476).
The spelling of 14042413435 in words is "fourteen billion, forty-two million, four hundred thirteen thousand, four hundred thirty-five".
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