Base | Representation |
---|---|
bin | 11111111011011100010001… |
… | …001000010011101011000001 |
3 | 200102012102111221112200020022 |
4 | 133323130101020103223001 |
5 | 121401202322220224441 |
6 | 1214354001241423225 |
7 | 41402213436312353 |
oct | 3773342110235301 |
9 | 612172457480208 |
10 | 140424243133121 |
11 | 4081a65043a352 |
12 | 138bb1aaa9ab15 |
13 | 6047c4582500c |
14 | 26967d90d90d3 |
15 | 1137b5440084b |
hex | 7fb711213ac1 |
140424243133121 has 2 divisors, whose sum is σ = 140424243133122. Its totient is φ = 140424243133120.
The previous prime is 140424243133117. The next prime is 140424243133201. The reversal of 140424243133121 is 121331342424041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80819111103025 + 59605132030096 = 8989945^2 + 7720436^2 .
It is a cyclic number.
It is not a de Polignac number, because 140424243133121 - 22 = 140424243133117 is a prime.
It is not a weakly prime, because it can be changed into another prime (140424203133121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70212121566560 + 70212121566561.
It is an arithmetic number, because the mean of its divisors is an integer number (70212121566561).
Almost surely, 2140424243133121 is an apocalyptic number.
It is an amenable number.
140424243133121 is a deficient number, since it is larger than the sum of its proper divisors (1).
140424243133121 is an equidigital number, since it uses as much as digits as its factorization.
140424243133121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 140424243133121 its reverse (121331342424041), we get a palindrome (261755585557162).
The spelling of 140424243133121 in words is "one hundred forty trillion, four hundred twenty-four billion, two hundred forty-three million, one hundred thirty-three thousand, one hundred twenty-one".
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