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140424243133121 is a prime number
BaseRepresentation
bin11111111011011100010001…
…001000010011101011000001
3200102012102111221112200020022
4133323130101020103223001
5121401202322220224441
61214354001241423225
741402213436312353
oct3773342110235301
9612172457480208
10140424243133121
114081a65043a352
12138bb1aaa9ab15
136047c4582500c
1426967d90d90d3
151137b5440084b
hex7fb711213ac1

140424243133121 has 2 divisors, whose sum is σ = 140424243133122. Its totient is φ = 140424243133120.

The previous prime is 140424243133117. The next prime is 140424243133201. The reversal of 140424243133121 is 121331342424041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 80819111103025 + 59605132030096 = 8989945^2 + 7720436^2 .

It is a cyclic number.

It is not a de Polignac number, because 140424243133121 - 22 = 140424243133117 is a prime.

It is not a weakly prime, because it can be changed into another prime (140424203133121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70212121566560 + 70212121566561.

It is an arithmetic number, because the mean of its divisors is an integer number (70212121566561).

Almost surely, 2140424243133121 is an apocalyptic number.

It is an amenable number.

140424243133121 is a deficient number, since it is larger than the sum of its proper divisors (1).

140424243133121 is an equidigital number, since it uses as much as digits as its factorization.

140424243133121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 140424243133121 its reverse (121331342424041), we get a palindrome (261755585557162).

The spelling of 140424243133121 in words is "one hundred forty trillion, four hundred twenty-four billion, two hundred forty-three million, one hundred thirty-three thousand, one hundred twenty-one".