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140424243133201 is a prime number
BaseRepresentation
bin11111111011011100010001…
…001000010011101100010001
3200102012102111221112200100021
4133323130101020103230101
5121401202322220230301
61214354001241423441
741402213436312526
oct3773342110235421
9612172457480307
10140424243133201
114081a65043a415
12138bb1aaa9ab81
136047c45825071
1426967d90d914d
151137b544008a1
hex7fb711213b11

140424243133201 has 2 divisors, whose sum is σ = 140424243133202. Its totient is φ = 140424243133200.

The previous prime is 140424243133121. The next prime is 140424243133217. The reversal of 140424243133201 is 102331342424041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121953149697600 + 18471093435601 = 11043240^2 + 4297801^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140424243133201 is a prime.

It is a super-3 number, since 3×1404242431332013 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (140424243533201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70212121566600 + 70212121566601.

It is an arithmetic number, because the mean of its divisors is an integer number (70212121566601).

Almost surely, 2140424243133201 is an apocalyptic number.

It is an amenable number.

140424243133201 is a deficient number, since it is larger than the sum of its proper divisors (1).

140424243133201 is an equidigital number, since it uses as much as digits as its factorization.

140424243133201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 140424243133201 its reverse (102331342424041), we get a palindrome (242755585557242).

The spelling of 140424243133201 in words is "one hundred forty trillion, four hundred twenty-four billion, two hundred forty-three million, one hundred thirty-three thousand, two hundred one".