Base | Representation |
---|---|
bin | 11111111011011101001010… |
… | …110100100101111000000111 |
3 | 200102012112000101211121102202 |
4 | 133323131022310211320013 |
5 | 121401211313011341320 |
6 | 1214354241255225115 |
7 | 41402246431362131 |
oct | 3773351264457007 |
9 | 612175011747382 |
10 | 140425211043335 |
11 | 4081aaa7835649 |
12 | 138bb41b07819b |
13 | 604806b207c5a |
14 | 269688b892051 |
15 | 1137bae393b75 |
hex | 7fb74ad25e07 |
140425211043335 has 16 divisors (see below), whose sum is σ = 168687947149344. Its totient is φ = 112221763809792.
The previous prime is 140425211043323. The next prime is 140425211043379. The reversal of 140425211043335 is 533340112524041.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140425211043335 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15927419 + ... + 23119971.
It is an arithmetic number, because the mean of its divisors is an integer number (10542996696834).
Almost surely, 2140425211043335 is an apocalyptic number.
140425211043335 is a deficient number, since it is larger than the sum of its proper divisors (28262736106009).
140425211043335 is a wasteful number, since it uses less digits than its factorization.
140425211043335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7196674.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 140425211043335 its reverse (533340112524041), we get a palindrome (673765323567376).
The spelling of 140425211043335 in words is "one hundred forty trillion, four hundred twenty-five billion, two hundred eleven million, forty-three thousand, three hundred thirty-five".
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