Base | Representation |
---|---|
bin | 1000001011001000010… |
… | …0101111100011110101 |
3 | 111102110120022102102011 |
4 | 2002302010233203311 |
5 | 4300043143310201 |
6 | 144302220044221 |
7 | 13100620622644 |
oct | 2026204574365 |
9 | 442416272364 |
10 | 140426541301 |
11 | 54611137a12 |
12 | 23270693671 |
13 | 1031c0671b7 |
14 | 6b2214135b |
15 | 39bd3c9151 |
hex | 20b212f8f5 |
140426541301 has 2 divisors, whose sum is σ = 140426541302. Its totient is φ = 140426541300.
The previous prime is 140426541263. The next prime is 140426541349. The reversal of 140426541301 is 103145624041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 138212932900 + 2213608401 = 371770^2 + 47049^2 .
It is a cyclic number.
It is not a de Polignac number, because 140426541301 - 213 = 140426533109 is a prime.
It is a super-2 number, since 2×1404265413012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140426541401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70213270650 + 70213270651.
It is an arithmetic number, because the mean of its divisors is an integer number (70213270651).
Almost surely, 2140426541301 is an apocalyptic number.
It is an amenable number.
140426541301 is a deficient number, since it is larger than the sum of its proper divisors (1).
140426541301 is an equidigital number, since it uses as much as digits as its factorization.
140426541301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
The spelling of 140426541301 in words is "one hundred forty billion, four hundred twenty-six million, five hundred forty-one thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.091 sec. • engine limits •