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14043001211431 is a prime number
BaseRepresentation
bin1100110001011010010000…
…0110010100101000100111
31211201111102220021211100221
43030112210012110220213
53320040031302231211
645511133220145211
72646400442540653
oct314264406245047
954644386254327
1014043001211431
1145246700a1255
1216a9764838207
137ab331a2325a
14367983479a63
15195456117c71
hexcc5a4194a27

14043001211431 has 2 divisors, whose sum is σ = 14043001211432. Its totient is φ = 14043001211430.

The previous prime is 14043001211417. The next prime is 14043001211467. The reversal of 14043001211431 is 13411210034041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14043001211431 - 213 = 14043001203239 is a prime.

It is a super-2 number, since 2×140430012114312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14043001211396 and 14043001211405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14043001211401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021500605715 + 7021500605716.

It is an arithmetic number, because the mean of its divisors is an integer number (7021500605716).

Almost surely, 214043001211431 is an apocalyptic number.

14043001211431 is a deficient number, since it is larger than the sum of its proper divisors (1).

14043001211431 is an equidigital number, since it uses as much as digits as its factorization.

14043001211431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14043001211431 its reverse (13411210034041), we get a palindrome (27454211245472).

The spelling of 14043001211431 in words is "fourteen trillion, forty-three billion, one million, two hundred eleven thousand, four hundred thirty-one".