Base | Representation |
---|---|
bin | 11111111011100001110000… |
… | …000101100001000011100011 |
3 | 200102012222201021222200110111 |
4 | 133323201300011201003203 |
5 | 121401301402042014243 |
6 | 1214400413415312151 |
7 | 41402512364143612 |
oct | 3773416005410343 |
9 | 612188637880414 |
10 | 140430131204323 |
11 | 408220a20713a4 |
12 | 1390037297b657 |
13 | 604867366180c |
14 | 2696bd70cd879 |
15 | 1137d9b2c939d |
hex | 7fb8701610e3 |
140430131204323 has 2 divisors, whose sum is σ = 140430131204324. Its totient is φ = 140430131204322.
The previous prime is 140430131204263. The next prime is 140430131204359. The reversal of 140430131204323 is 323402131034041.
It is a strong prime.
It is an emirp because it is prime and its reverse (323402131034041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 140430131204323 - 217 = 140430131073251 is a prime.
It is not a weakly prime, because it can be changed into another prime (140430131204393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70215065602161 + 70215065602162.
It is an arithmetic number, because the mean of its divisors is an integer number (70215065602162).
Almost surely, 2140430131204323 is an apocalyptic number.
140430131204323 is a deficient number, since it is larger than the sum of its proper divisors (1).
140430131204323 is an equidigital number, since it uses as much as digits as its factorization.
140430131204323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 140430131204323 its reverse (323402131034041), we get a palindrome (463832262238364).
The spelling of 140430131204323 in words is "one hundred forty trillion, four hundred thirty billion, one hundred thirty-one million, two hundred four thousand, three hundred twenty-three".
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