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140430131244323 is a prime number
BaseRepresentation
bin11111111011100001110000…
…000101101010110100100011
3200102012222201022001201022222
4133323201300011222310203
5121401301402044304243
61214400413420221255
741402512364401334
oct3773416005526443
9612188638051288
10140430131244323
11408220a2099458
121390037299a82b
136048673676a9b
142696bd710028b
151137d9b2d6168
hex7fb87016ad23

140430131244323 has 2 divisors, whose sum is σ = 140430131244324. Its totient is φ = 140430131244322.

The previous prime is 140430131244257. The next prime is 140430131244331. The reversal of 140430131244323 is 323442131034041.

It is a strong prime.

It is an emirp because it is prime and its reverse (323442131034041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140430131244323 - 218 = 140430130982179 is a prime.

It is a super-2 number, since 2×1404301312443232 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140430131204323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70215065622161 + 70215065622162.

It is an arithmetic number, because the mean of its divisors is an integer number (70215065622162).

Almost surely, 2140430131244323 is an apocalyptic number.

140430131244323 is a deficient number, since it is larger than the sum of its proper divisors (1).

140430131244323 is an equidigital number, since it uses as much as digits as its factorization.

140430131244323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 140430131244323 its reverse (323442131034041), we get a palindrome (463872262278364).

The spelling of 140430131244323 in words is "one hundred forty trillion, four hundred thirty billion, one hundred thirty-one million, two hundred forty-four thousand, three hundred twenty-three".