14043241213033 has 4 divisors (see below), whose sum is σ = 14043386894148. Its totient is φ = 14043095531920.

The previous prime is 14043241213021. The next prime is 14043241213049. The reversal of 14043241213033 is 33031214234041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7286501219904 + 6756739993129 = 2699352^2 + 2599373^2 .

It is a cyclic number.

It is not a de Polignac number, because 14043241213033 - 2³³ = 14034651278441 is a prime.

It is a super-3 number, since 3×14043241213033³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14043241212986 and 14043241213004.

It is not an unprimeable number, because it can be changed into a prime (14043241213633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72695866 + ... + 72888787.

It is an arithmetic number, because the mean of its divisors is an integer number (3510846723537).

Almost surely, 2^{14043241213033} is an apocalyptic number.

It is an amenable number.

14043241213033 is a deficient number, since it is larger than the sum of its proper divisors (145681115).

14043241213033 is an equidigital number, since it uses as much as digits as its factorization.

14043241213033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 145681114.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 14043241213033 its reverse (33031214234041), we get a palindrome (47074455447074).

The spelling of 14043241213033 in words is "fourteen trillion, forty-three billion, two hundred forty-one million, two hundred thirteen thousand, thirty-three".