Base | Representation |
---|---|
bin | 1100110001011011011000… |
… | …0010111000110101010011 |
3 | 1211201112012212211202121212 |
4 | 3030112312002320311103 |
5 | 3320041140342113021 |
6 | 45511223133410335 |
7 | 2646411060006104 |
oct | 314266602706523 |
9 | 54645185752555 |
10 | 14043302301011 |
11 | 452480504a315 |
12 | 16a98296399ab |
13 | 7ab37c212c79 |
14 | 3679b14543ab |
15 | 19547278e85b |
hex | cc5b60b8d53 |
14043302301011 has 2 divisors, whose sum is σ = 14043302301012. Its totient is φ = 14043302301010.
The previous prime is 14043302300983. The next prime is 14043302301023. The reversal of 14043302301011 is 11010320334041.
14043302301011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14043302301011 - 222 = 14043298106707 is a prime.
It is not a weakly prime, because it can be changed into another prime (14043302301211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021651150505 + 7021651150506.
It is an arithmetic number, because the mean of its divisors is an integer number (7021651150506).
Almost surely, 214043302301011 is an apocalyptic number.
14043302301011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14043302301011 is an equidigital number, since it uses as much as digits as its factorization.
14043302301011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 14043302301011 its reverse (11010320334041), we get a palindrome (25053622635052).
The spelling of 14043302301011 in words is "fourteen trillion, forty-three billion, three hundred two million, three hundred one thousand, eleven".
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