Base | Representation |
---|---|
bin | 11010001010000101… |
… | …11111000100100101 |
3 | 1100020200222012001021 |
4 | 31011002333010211 |
5 | 212230041444141 |
6 | 10241300531141 |
7 | 1005002120545 |
oct | 150502770445 |
9 | 40220865037 |
10 | 14043312421 |
11 | 5a570a1526 |
12 | 287b0b0ab1 |
13 | 142a595328 |
14 | 97314d325 |
15 | 572d3b6d1 |
hex | 3450bf125 |
14043312421 has 4 divisors (see below), whose sum is σ = 14044967872. Its totient is φ = 14041656972.
The previous prime is 14043312373. The next prime is 14043312487. The reversal of 14043312421 is 12421334041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14043312421 - 221 = 14041215269 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14043322421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 814935 + ... + 831988.
It is an arithmetic number, because the mean of its divisors is an integer number (3511241968).
Almost surely, 214043312421 is an apocalyptic number.
It is an amenable number.
14043312421 is a deficient number, since it is larger than the sum of its proper divisors (1655451).
14043312421 is an equidigital number, since it uses as much as digits as its factorization.
14043312421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1655450.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14043312421 its reverse (12421334041), we get a palindrome (26464646462).
The spelling of 14043312421 in words is "fourteen billion, forty-three million, three hundred twelve thousand, four hundred twenty-one".
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