14043314331050 has 12 divisors (see below), whose sum is σ = 26120564655846. Its totient is φ = 5617325732400.

The previous prime is 14043314330999. The next prime is 14043314331061. The reversal of 14043314331050 is 5013341334041.

It can be written as a sum of positive squares in 3 ways, for example, as 8443214529841 + 5600099801209 = 2905721^2 + 2366453^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14043314330998 and 14043314331016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 140433143261 + ... + 140433143360.

Almost surely, 2^{14043314331050} is an apocalyptic number.

14043314331050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14043314331050 is a deficient number, since it is larger than the sum of its proper divisors (12077250324796).

14043314331050 is a wasteful number, since it uses less digits than its factorization.

14043314331050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 280866286633 (or 280866286628 counting only the distinct ones).

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 14043314331050 its reverse (5013341334041), we get a palindrome (19056655665091).

The spelling of 14043314331050 in words is "fourteen trillion, forty-three billion, three hundred fourteen million, three hundred thirty-one thousand, fifty".