Base | Representation |
---|---|
bin | 1000001011001001110… |
… | …1111111101111110111 |
3 | 111102111000202202012212 |
4 | 2002302131333233313 |
5 | 4300101342124312 |
6 | 144303014004035 |
7 | 13101031113653 |
oct | 2026235775767 |
9 | 442430682185 |
10 | 140433161207 |
11 | 54614949609 |
12 | 2327294661b |
13 | 103205443c1 |
14 | 6b22d85a63 |
15 | 39bdc85822 |
hex | 20b277fbf7 |
140433161207 has 2 divisors, whose sum is σ = 140433161208. Its totient is φ = 140433161206.
The previous prime is 140433161201. The next prime is 140433161243. The reversal of 140433161207 is 702161334041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140433161207 - 222 = 140428966903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140433161201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70216580603 + 70216580604.
It is an arithmetic number, because the mean of its divisors is an integer number (70216580604).
Almost surely, 2140433161207 is an apocalyptic number.
140433161207 is a deficient number, since it is larger than the sum of its proper divisors (1).
140433161207 is an equidigital number, since it uses as much as digits as its factorization.
140433161207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 140433161207 its reverse (702161334041), we get a palindrome (842594495248).
The spelling of 140433161207 in words is "one hundred forty billion, four hundred thirty-three million, one hundred sixty-one thousand, two hundred seven".
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