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14044053200503 = 37379569005419
BaseRepresentation
bin1100110001011110001011…
…0011010101111001110111
31211201121011012210102002011
43030113202303111321313
53320044210104404003
645511425440025051
72646435505362334
oct314274263257167
954647135712064
1014044053200503
11452505a9a4207
1216a99b9002187
137ab46b963cb1
14367a4307b98b
151954b866846d
hexcc5e2cd5e77

14044053200503 has 4 divisors (see below), whose sum is σ = 14423622205960. Its totient is φ = 13664484195048.

The previous prime is 14044053200477. The next prime is 14044053200521. The reversal of 14044053200503 is 30500235044041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14044053200503 - 225 = 14044019646071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14044053200803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189784502673 + ... + 189784502746.

It is an arithmetic number, because the mean of its divisors is an integer number (3605905551490).

Almost surely, 214044053200503 is an apocalyptic number.

14044053200503 is a deficient number, since it is larger than the sum of its proper divisors (379569005457).

14044053200503 is an equidigital number, since it uses as much as digits as its factorization.

14044053200503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 379569005456.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 14044053200503 its reverse (30500235044041), we get a palindrome (44544288244544).

The spelling of 14044053200503 in words is "fourteen trillion, forty-four billion, fifty-three million, two hundred thousand, five hundred three".

Divisors: 1 37 379569005419 14044053200503