Base | Representation |
---|---|
bin | 1100110001011110001011… |
… | …0011010101111001110111 |
3 | 1211201121011012210102002011 |
4 | 3030113202303111321313 |
5 | 3320044210104404003 |
6 | 45511425440025051 |
7 | 2646435505362334 |
oct | 314274263257167 |
9 | 54647135712064 |
10 | 14044053200503 |
11 | 452505a9a4207 |
12 | 16a99b9002187 |
13 | 7ab46b963cb1 |
14 | 367a4307b98b |
15 | 1954b866846d |
hex | cc5e2cd5e77 |
14044053200503 has 4 divisors (see below), whose sum is σ = 14423622205960. Its totient is φ = 13664484195048.
The previous prime is 14044053200477. The next prime is 14044053200521. The reversal of 14044053200503 is 30500235044041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14044053200503 - 225 = 14044019646071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14044053200803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189784502673 + ... + 189784502746.
It is an arithmetic number, because the mean of its divisors is an integer number (3605905551490).
Almost surely, 214044053200503 is an apocalyptic number.
14044053200503 is a deficient number, since it is larger than the sum of its proper divisors (379569005457).
14044053200503 is an equidigital number, since it uses as much as digits as its factorization.
14044053200503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 379569005456.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 14044053200503 its reverse (30500235044041), we get a palindrome (44544288244544).
The spelling of 14044053200503 in words is "fourteen trillion, forty-four billion, fifty-three million, two hundred thousand, five hundred three".
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