140441104123141 has 4 divisors (see below), whose sum is σ = 140441129698752. Its totient is φ = 140441078547532.

The previous prime is 140441104123031. The next prime is 140441104123163. The reversal of 140441104123141 is 141321401144041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140441104123141 - 2²⁵ = 140441070568709 is a prime.

It is a super-3 number, since 3×140441104123141³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140441104121141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 813415 + ... + 16779268.

It is an arithmetic number, because the mean of its divisors is an integer number (35110282424688).

Almost surely, 2^{140441104123141} is an apocalyptic number.

It is an amenable number.

140441104123141 is a deficient number, since it is larger than the sum of its proper divisors (25575611).

140441104123141 is an equidigital number, since it uses as much as digits as its factorization.

140441104123141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25575610.

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 140441104123141 its reverse (141321401144041), we get a palindrome (281762505267182).

The spelling of 140441104123141 in words is "one hundred forty trillion, four hundred forty-one billion, one hundred four million, one hundred twenty-three thousand, one hundred forty-one".