Base | Representation |
---|---|
bin | 1100110001011110011001… |
… | …1000110001011110101111 |
3 | 1211201121022101222001001001 |
4 | 3030113212120301132233 |
5 | 3320044321004010211 |
6 | 45511435425101131 |
7 | 2646440135526142 |
oct | 314274630613657 |
9 | 54647271861031 |
10 | 14044113344431 |
11 | 4525090943235 |
12 | 16a9a151877a7 |
13 | 7ab47b261611 |
14 | 367a4b056059 |
15 | 1954bda98ac1 |
hex | cc5e66317af |
14044113344431 has 2 divisors, whose sum is σ = 14044113344432. Its totient is φ = 14044113344430.
The previous prime is 14044113344369. The next prime is 14044113344441. The reversal of 14044113344431 is 13444331144041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14044113344431 - 217 = 14044113213359 is a prime.
It is a super-2 number, since 2×140441133444312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14044113344441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022056672215 + 7022056672216.
It is an arithmetic number, because the mean of its divisors is an integer number (7022056672216).
Almost surely, 214044113344431 is an apocalyptic number.
14044113344431 is a deficient number, since it is larger than the sum of its proper divisors (1).
14044113344431 is an equidigital number, since it uses as much as digits as its factorization.
14044113344431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 37.
Adding to 14044113344431 its reverse (13444331144041), we get a palindrome (27488444488472).
The spelling of 14044113344431 in words is "fourteen trillion, forty-four billion, one hundred thirteen million, three hundred forty-four thousand, four hundred thirty-one".
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