Base | Representation |
---|---|
bin | 10100011011111101100… |
… | …100000100111001111111 |
3 | 11222021000222122100012221 |
4 | 110123331210010321333 |
5 | 141002214314301143 |
6 | 2553102325510211 |
7 | 203315450126032 |
oct | 24337544047177 |
9 | 4867028570187 |
10 | 1404413431423 |
11 | 4a1676850682 |
12 | 1a8227272367 |
13 | a2588090562 |
14 | 4bd8c81d019 |
15 | 267ea84d2ed |
hex | 146fd904e7f |
1404413431423 has 2 divisors, whose sum is σ = 1404413431424. Its totient is φ = 1404413431422.
The previous prime is 1404413431409. The next prime is 1404413431441. The reversal of 1404413431423 is 3241343144041.
It is a weak prime.
It is an emirp because it is prime and its reverse (3241343144041) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1404413431423 is a prime.
It is a super-2 number, since 2×14044134314232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1404413431493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702206715711 + 702206715712.
It is an arithmetic number, because the mean of its divisors is an integer number (702206715712).
Almost surely, 21404413431423 is an apocalyptic number.
1404413431423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1404413431423 is an equidigital number, since it uses as much as digits as its factorization.
1404413431423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 1404413431423 its reverse (3241343144041), we get a palindrome (4645756575464).
The spelling of 1404413431423 in words is "one trillion, four hundred four billion, four hundred thirteen million, four hundred thirty-one thousand, four hundred twenty-three".
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