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1404414113 is a prime number
BaseRepresentation
bin101001110110101…
…1010100010100001
310121212122121222112
41103231122202201
510334012222423
6351205245105
746542215534
oct12355324241
93555577875
101404414113
11660834123
12332403795
13194c6598b
14d4740a1b
1583467a78
hex53b5a8a1

1404414113 has 2 divisors, whose sum is σ = 1404414114. Its totient is φ = 1404414112.

The previous prime is 1404414107. The next prime is 1404414157. The reversal of 1404414113 is 3114144041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 827597824 + 576816289 = 28768^2 + 24017^2 .

It is a cyclic number.

It is not a de Polignac number, because 1404414113 - 212 = 1404410017 is a prime.

It is not a weakly prime, because it can be changed into another prime (1404414313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702207056 + 702207057.

It is an arithmetic number, because the mean of its divisors is an integer number (702207057).

Almost surely, 21404414113 is an apocalyptic number.

It is an amenable number.

1404414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1404414113 is an equidigital number, since it uses as much as digits as its factorization.

1404414113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

The square root of 1404414113 is about 37475.5135121588. The cubic root of 1404414113 is about 1119.8634274903.

Adding to 1404414113 its reverse (3114144041), we get a palindrome (4518558154).

The spelling of 1404414113 in words is "one billion, four hundred four million, four hundred fourteen thousand, one hundred thirteen".