140442113 has 4 divisors (see below), whose sum is σ = 160505280. Its totient is φ = 120378948.

The previous prime is 140442079. The next prime is 140442149. The reversal of 140442113 is 311244041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140442113 - 2⁸ = 140441857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140442413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10031573 + ... + 10031586.

It is an arithmetic number, because the mean of its divisors is an integer number (40126320).

Almost surely, 2^140442113 is an apocalyptic number.

It is an amenable number.

140442113 is a deficient number, since it is larger than the sum of its proper divisors (20063167).

140442113 is an equidigital number, since it uses as much as digits as its factorization.

140442113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20063166.

The product of its (nonzero) digits is 384, while the sum is 20.

The square root of 140442113 is about 11850.8275238483. The cubic root of 140442113 is about 519.7954237183.

Adding to 140442113 its reverse (311244041), we get a palindrome (451686154).

The spelling of 140442113 in words is "one hundred forty million, four hundred forty-two thousand, one hundred thirteen".