1404422240131 has 4 divisors (see below), whose sum is σ = 1404429415200. Its totient is φ = 1404415065064.

The previous prime is 1404422240093. The next prime is 1404422240189. The reversal of 1404422240131 is 1310422244041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1404422240131 - 2³¹ = 1402274756483 is a prime.

It is a super-2 number, since 2×1404422240131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1404422240131.

It is not an unprimeable number, because it can be changed into a prime (1404422240731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3285451 + ... + 3688228.

It is an arithmetic number, because the mean of its divisors is an integer number (351107353800).

Almost surely, 2^{1404422240131} is an apocalyptic number.

1404422240131 is a deficient number, since it is larger than the sum of its proper divisors (7175069).

1404422240131 is an equidigital number, since it uses as much as digits as its factorization.

1404422240131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7175068.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 1404422240131 its reverse (1310422244041), we get a palindrome (2714844484172).

The spelling of 1404422240131 in words is "one trillion, four hundred four billion, four hundred twenty-two million, two hundred forty thousand, one hundred thirty-one".