Base | Representation |
---|---|
bin | 11010001010001100… |
… | …11111110110101011 |
3 | 1100020202200222000122 |
4 | 31011012133312223 |
5 | 212230310430011 |
6 | 10241332353455 |
7 | 1005013004045 |
oct | 150506376653 |
9 | 40222628018 |
10 | 14044233131 |
11 | 5a57670245 |
12 | 287b47588b |
13 | 142a828426 |
14 | 97330ca95 |
15 | 572e6e3db |
hex | 34519fdab |
14044233131 has 2 divisors, whose sum is σ = 14044233132. Its totient is φ = 14044233130.
The previous prime is 14044233121. The next prime is 14044233179. The reversal of 14044233131 is 13133244041.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (13133244041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14044233131 - 230 = 12970491307 is a prime.
It is a super-2 number, since 2×140442331312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14044233131.
It is not a weakly prime, because it can be changed into another prime (14044233101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022116565 + 7022116566.
It is an arithmetic number, because the mean of its divisors is an integer number (7022116566).
Almost surely, 214044233131 is an apocalyptic number.
14044233131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14044233131 is an equidigital number, since it uses as much as digits as its factorization.
14044233131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 14044233131 its reverse (13133244041), we get a palindrome (27177477172).
The spelling of 14044233131 in words is "fourteen billion, forty-four million, two hundred thirty-three thousand, one hundred thirty-one".
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