14044235132803 has 2 divisors, whose sum is σ = 14044235132804. Its totient is φ = 14044235132802.

The previous prime is 14044235132797. The next prime is 14044235132843. The reversal of 14044235132803 is 30823153244041.

It is an a-pointer prime, because the next prime (14044235132843) can be obtained adding 14044235132803 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14044235132803 - 2⁵ = 14044235132771 is a prime.

It is not a weakly prime, because it can be changed into another prime (14044235132843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7022117566401 + 7022117566402.

It is an arithmetic number, because the mean of its divisors is an integer number (7022117566402).

Almost surely, 2^{14044235132803} is an apocalyptic number.

14044235132803 is a deficient number, since it is larger than the sum of its proper divisors (1).

14044235132803 is an equidigital number, since it uses as much as digits as its factorization.

14044235132803 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 276480, while the sum is 40.

Adding to 14044235132803 its reverse (30823153244041), we get a palindrome (44867388376844).

The spelling of 14044235132803 in words is "fourteen trillion, forty-four billion, two hundred thirty-five million, one hundred thirty-two thousand, eight hundred three".