1404433452011 has 2 divisors, whose sum is σ = 1404433452012. Its totient is φ = 1404433452010.

The previous prime is 1404433452001. The next prime is 1404433452013. The reversal of 1404433452011 is 1102543344041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1404433452011 is a prime.

It is a super-2 number, since 2×1404433452011² (a number of 25 digits) contains 22 as substring.

Together with 1404433452013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1404433452013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 702216726005 + 702216726006.

It is an arithmetic number, because the mean of its divisors is an integer number (702216726006).

Almost surely, 2^{1404433452011} is an apocalyptic number.

1404433452011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1404433452011 is an equidigital number, since it uses as much as digits as its factorization.

1404433452011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 1404433452011 its reverse (1102543344041), we get a palindrome (2506976796052).

The spelling of 1404433452011 in words is "one trillion, four hundred four billion, four hundred thirty-three million, four hundred fifty-two thousand, eleven".