14044424311 has 4 divisors (see below), whose sum is σ = 14064233800. Its totient is φ = 14024614824.

The previous prime is 14044424299. The next prime is 14044424323. The reversal of 14044424311 is 11342444041.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (14044424299) and next prime (14044424323).

It is a cyclic number.

It is not a de Polignac number, because 14044424311 - 2⁵ = 14044424279 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14044424311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14044424341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9903681 + ... + 9905098.

It is an arithmetic number, because the mean of its divisors is an integer number (3516058450).

Almost surely, 2^14044424311 is an apocalyptic number.

14044424311 is a deficient number, since it is larger than the sum of its proper divisors (19809489).

14044424311 is an equidigital number, since it uses as much as digits as its factorization.

14044424311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19809488.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 14044424311 its reverse (11342444041), we get a palindrome (25386868352).

The spelling of 14044424311 in words is "fourteen billion, forty-four million, four hundred twenty-four thousand, three hundred eleven".