Base | Representation |
---|---|
bin | 1000001011001110011… |
… | …1011110010110001011 |
3 | 111102112101000100111111 |
4 | 2002303213132112023 |
5 | 4300121310014201 |
6 | 144304542511151 |
7 | 13101353616643 |
oct | 2026347362613 |
9 | 442471010444 |
10 | 140452423051 |
11 | 54624805296 |
12 | 232792954b7 |
13 | 10324529845 |
14 | 6b2575b523 |
15 | 39c07dcb51 |
hex | 20b39de58b |
140452423051 has 2 divisors, whose sum is σ = 140452423052. Its totient is φ = 140452423050.
The previous prime is 140452423049. The next prime is 140452423073. The reversal of 140452423051 is 150324254041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140452423051 - 21 = 140452423049 is a prime.
It is a super-2 number, since 2×1404524230512 (a number of 23 digits) contains 22 as substring.
Together with 140452423049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (140452420051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70226211525 + 70226211526.
It is an arithmetic number, because the mean of its divisors is an integer number (70226211526).
Almost surely, 2140452423051 is an apocalyptic number.
140452423051 is a deficient number, since it is larger than the sum of its proper divisors (1).
140452423051 is an equidigital number, since it uses as much as digits as its factorization.
140452423051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 140452423051 its reverse (150324254041), we get a palindrome (290776677092).
The spelling of 140452423051 in words is "one hundred forty billion, four hundred fifty-two million, four hundred twenty-three thousand, fifty-one".
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