140501034152113 has 2 divisors, whose sum is σ = 140501034152114. Its totient is φ = 140501034152112.

The previous prime is 140501034152051. The next prime is 140501034152117. The reversal of 140501034152113 is 311251430105041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86505475892224 + 53995558259889 = 9300832^2 + 7348167^2 .

It is a cyclic number.

It is not a de Polignac number, because 140501034152113 - 2⁴⁵ = 105316662063281 is a prime.

It is not a weakly prime, because it can be changed into another prime (140501034152117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70250517076056 + 70250517076057.

It is an arithmetic number, because the mean of its divisors is an integer number (70250517076057).

Almost surely, 2^{140501034152113} is an apocalyptic number.

It is an amenable number.

140501034152113 is a deficient number, since it is larger than the sum of its proper divisors (1).

140501034152113 is an equidigital number, since it uses as much as digits as its factorization.

140501034152113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 140501034152113 its reverse (311251430105041), we get a palindrome (451752464257154).

The spelling of 140501034152113 in words is "one hundred forty trillion, five hundred one billion, thirty-four million, one hundred fifty-two thousand, one hundred thirteen".