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14050212314981 is a prime number
BaseRepresentation
bin1100110001110101000111…
…1010011111111101100101
31211202012001110020211210012
43030131101322133331211
53320144313323034411
645514324535140005
72650044234111323
oct314352172377545
954665043224705
1014050212314981
114527730622067
1216ab037814605
137abc109a042b
14368069068d13
1519572923118b
hexcc751e9ff65

14050212314981 has 2 divisors, whose sum is σ = 14050212314982. Its totient is φ = 14050212314980.

The previous prime is 14050212314959. The next prime is 14050212314987. The reversal of 14050212314981 is 18941321205041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10068627072100 + 3981585242881 = 3173110^2 + 1995391^2 .

It is a cyclic number.

It is not a de Polignac number, because 14050212314981 - 26 = 14050212314917 is a prime.

It is a super-2 number, since 2×140502123149812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14050212314987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7025106157490 + 7025106157491.

It is an arithmetic number, because the mean of its divisors is an integer number (7025106157491).

Almost surely, 214050212314981 is an apocalyptic number.

It is an amenable number.

14050212314981 is a deficient number, since it is larger than the sum of its proper divisors (1).

14050212314981 is an equidigital number, since it uses as much as digits as its factorization.

14050212314981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 41.

The spelling of 14050212314981 in words is "fourteen trillion, fifty billion, two hundred twelve million, three hundred fourteen thousand, nine hundred eighty-one".