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14050214412153 = 326237178503823
BaseRepresentation
bin1100110001110101001000…
…0010011111111101111001
31211202012001121012101120020
43030131102002133331321
53320144314342142103
645514325052121053
72650044260664453
oct314352202377571
954665047171506
1014050214412153
114527731824767
1216ab038466189
137abc11255b6a
143680694532d3
151957294e7753
hexcc75209ff79

14050214412153 has 8 divisors (see below), whose sum is σ = 18734333336448. Its totient is φ = 9366452547984.

The previous prime is 14050214412139. The next prime is 14050214412181. The reversal of 14050214412153 is 35121441205041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14050214412153 - 212 = 14050214408057 is a prime.

It is a super-3 number, since 3×140502144121533 (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (14050214412133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 89173201 + ... + 89330622.

It is an arithmetic number, because the mean of its divisors is an integer number (2341791667056).

Almost surely, 214050214412153 is an apocalyptic number.

It is an amenable number.

14050214412153 is a deficient number, since it is larger than the sum of its proper divisors (4684118924295).

14050214412153 is a wasteful number, since it uses less digits than its factorization.

14050214412153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 178530063.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 14050214412153 its reverse (35121441205041), we get a palindrome (49171655617194).

The spelling of 14050214412153 in words is "fourteen trillion, fifty billion, two hundred fourteen million, four hundred twelve thousand, one hundred fifty-three".

Divisors: 1 3 26237 78711 178503823 535511469 4683404804051 14050214412153