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14050214412133 is a prime number
BaseRepresentation
bin1100110001110101001000…
…0010011111111101100101
31211202012001121012101112111
43030131102002133331211
53320144314342142013
645514325052121021
72650044260664424
oct314352202377545
954665047171474
1014050214412133
114527731824749
1216ab038466171
137abc11255b53
143680694532bb
151957294e773d
hexcc75209ff65

14050214412133 has 2 divisors, whose sum is σ = 14050214412134. Its totient is φ = 14050214412132.

The previous prime is 14050214412107. The next prime is 14050214412139. The reversal of 14050214412133 is 33121441205041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11702844167364 + 2347370244769 = 3420942^2 + 1532113^2 .

It is a cyclic number.

It is not a de Polignac number, because 14050214412133 - 221 = 14050212314981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14050214412095 and 14050214412104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14050214412139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7025107206066 + 7025107206067.

It is an arithmetic number, because the mean of its divisors is an integer number (7025107206067).

Almost surely, 214050214412133 is an apocalyptic number.

It is an amenable number.

14050214412133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14050214412133 is an equidigital number, since it uses as much as digits as its factorization.

14050214412133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 14050214412133 its reverse (33121441205041), we get a palindrome (47171655617174).

The spelling of 14050214412133 in words is "fourteen trillion, fifty billion, two hundred fourteen million, four hundred twelve thousand, one hundred thirty-three".