Base | Representation |
---|---|
bin | 11010001010111010… |
… | …11001001011101001 |
3 | 1100021011222220012021 |
4 | 31011131121023221 |
5 | 212233330010423 |
6 | 10242105144441 |
7 | 1005115012405 |
oct | 150535311351 |
9 | 40234886167 |
10 | 14050235113 |
11 | 5a5aa9a662 |
12 | 288148b121 |
13 | 142bb4a2b5 |
14 | 974032105 |
15 | 57375795d |
hex | 3457592e9 |
14050235113 has 2 divisors, whose sum is σ = 14050235114. Its totient is φ = 14050235112.
The previous prime is 14050235099. The next prime is 14050235137. The reversal of 14050235113 is 31153205041.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14024954329 + 25280784 = 118427^2 + 5028^2 .
It is a cyclic number.
It is not a de Polignac number, because 14050235113 - 25 = 14050235081 is a prime.
It is not a weakly prime, because it can be changed into another prime (14050235813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7025117556 + 7025117557.
It is an arithmetic number, because the mean of its divisors is an integer number (7025117557).
Almost surely, 214050235113 is an apocalyptic number.
It is an amenable number.
14050235113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14050235113 is an equidigital number, since it uses as much as digits as its factorization.
14050235113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
The spelling of 14050235113 in words is "fourteen billion, fifty million, two hundred thirty-five thousand, one hundred thirteen".
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