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140505332145 = 359367022143
BaseRepresentation
bin1000001011011011000…
…1010011100110110001
3111102200001120102010120
42002312301103212301
54300223331112040
6144314112520453
713102565421603
oct2026661234661
9442601512116
10140505332145
1154651662712
1223292b50129
13103324930b9
146b2c7b1173
1539c528e7d0
hex20b6c539b1

140505332145 has 8 divisors (see below), whose sum is σ = 224808531456. Its totient is φ = 74936177136.

The previous prime is 140505332117. The next prime is 140505332171. The reversal of 140505332145 is 541233505041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 140505332145 - 213 = 140505323953 is a prime.

It is a super-2 number, since 2×1405053321452 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4683511057 + ... + 4683511086.

It is an arithmetic number, because the mean of its divisors is an integer number (28101066432).

Almost surely, 2140505332145 is an apocalyptic number.

140505332145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

140505332145 is a deficient number, since it is larger than the sum of its proper divisors (84303199311).

140505332145 is an equidigital number, since it uses as much as digits as its factorization.

140505332145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9367022151.

The product of its (nonzero) digits is 36000, while the sum is 33.

Adding to 140505332145 its reverse (541233505041), we get a palindrome (681738837186).

The spelling of 140505332145 in words is "one hundred forty billion, five hundred five million, three hundred thirty-two thousand, one hundred forty-five".

Divisors: 1 3 5 15 9367022143 28101066429 46835110715 140505332145