Base | Representation |
---|---|
bin | 11111111100110101111010… |
… | …100011110111001010001011 |
3 | 200102112121222100011101100121 |
4 | 133330311322203313022023 |
5 | 121404241441304311210 |
6 | 1214510121015044111 |
7 | 41412162005621635 |
oct | 3774657243671213 |
9 | 612477870141317 |
10 | 140520501244555 |
11 | 40857456655163 |
12 | 13915993670637 |
13 | 60540460357c3 |
14 | 269b32b1d3a55 |
15 | 113a3d9d9c6da |
hex | 7fcd7a8f728b |
140520501244555 has 16 divisors (see below), whose sum is σ = 178545250918944. Its totient is φ = 105802749913600.
The previous prime is 140520501244547. The next prime is 140520501244573. The reversal of 140520501244555 is 555442105025041.
It is not a de Polignac number, because 140520501244555 - 23 = 140520501244547 is a prime.
It is a super-2 number, since 2×1405205012445552 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2695080 + ... + 16979530.
It is an arithmetic number, because the mean of its divisors is an integer number (11159078182434).
Almost surely, 2140520501244555 is an apocalyptic number.
140520501244555 is a deficient number, since it is larger than the sum of its proper divisors (38024749674389).
140520501244555 is a wasteful number, since it uses less digits than its factorization.
140520501244555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14400206.
The product of its (nonzero) digits is 800000, while the sum is 43.
Adding to 140520501244555 its reverse (555442105025041), we get a palindrome (695962606269596).
The spelling of 140520501244555 in words is "one hundred forty trillion, five hundred twenty billion, five hundred one million, two hundred forty-four thousand, five hundred fifty-five".
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