Base | Representation |
---|---|
bin | 1100110001111101010001… |
… | …0101100010111011111100 |
3 | 1211202101200221121021022120 |
4 | 3030133110111202323330 |
5 | 3320213304003140012 |
6 | 45515330022242540 |
7 | 2650152403643562 |
oct | 314372425427374 |
9 | 54671627537276 |
10 | 14052400443132 |
11 | 4528653783137 |
12 | 16ab548586450 |
13 | 7ac19c10620c |
14 | 3681d58d5a32 |
15 | 1958063a558c |
hex | cc7d4562efc |
14052400443132 has 24 divisors (see below), whose sum is σ = 32789034526416. Its totient is φ = 4684119172608.
The previous prime is 14052400443121. The next prime is 14052400443187. The reversal of 14052400443132 is 23134400425041.
It is a junction number, because it is equal to n+sod(n) for n = 14052400443093 and 14052400443102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2767858 + ... + 5980454.
It is an arithmetic number, because the mean of its divisors is an integer number (1366209771934).
Almost surely, 214052400443132 is an apocalyptic number.
14052400443132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
14052400443132 is an abundant number, since it is smaller than the sum of its proper divisors (18736634083284).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14052400443132 is a wasteful number, since it uses less digits than its factorization.
14052400443132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3577117 (or 3577115 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 33.
Adding to 14052400443132 its reverse (23134400425041), we get a palindrome (37186800868173).
The spelling of 14052400443132 in words is "fourteen trillion, fifty-two billion, four hundred million, four hundred forty-three thousand, one hundred thirty-two".
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